(5+v)(3v+7)=0

Solution for (5+v)(3v+7)=0 equation:

(5+v)(3v+7)=0

We add all the numbers together, and all the variables

(v+5)(3v+7)=0

We multiply parentheses ..

(+3v^2+7v+15v+35)=0

We get rid of parentheses

3v^2+7v+15v+35=0

We add all the numbers together, and all the variables

3v^2+22v+35=0

a = 3; b = 22; c = +35;
Δ = b2-4ac
Δ = 222-4·3·35
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-8}{2*3}=\frac{-30}{6}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+8}{2*3}=\frac{-14}{6}
=-2+1/3
$