(5+x)(x-2)+10=0

Solution for (5+x)(x-2)+10=0 equation:

(5+x)(x-2)+10=0

We add all the numbers together, and all the variables

(x+5)(x-2)+10=0

We multiply parentheses ..

(+x^2-2x+5x-10)+10=0

We get rid of parentheses

x^2-2x+5x-10+10=0

We add all the numbers together, and all the variables

x^2+3x=0

a = 1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·1·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*1}=\frac{0}{2}
=0
$