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(5+x)(x-2)=60
We move all terms to the left:
(5+x)(x-2)-(60)=0
We add all the numbers together, and all the variables
(x+5)(x-2)-60=0
We multiply parentheses ..
(+x^2-2x+5x-10)-60=0
We get rid of parentheses
x^2-2x+5x-10-60=0
We add all the numbers together, and all the variables
x^2+3x-70=0
a = 1; b = 3; c = -70;
Δ = b2-4ac
Δ = 32-4·1·(-70)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-17}{2*1}=\frac{-20}{2} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+17}{2*1}=\frac{14}{2} =7 $
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