(5-2i)(-2+i)-6i(3+4i)=0

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Solution for (5-2i)(-2+i)-6i(3+4i)=0 equation: 



(5-2i)(-2+i)-6i(3+4i)=0

We add all the numbers together, and all the variables

(-2i+5)(i-2)-6i(4i+3)=0

We multiply parentheses

-24i^2+(-2i+5)(i-2)-18i=0

We multiply parentheses ..

-24i^2+(-2i^2+4i+5i-10)-18i=0

We get rid of parentheses

-24i^2-2i^2+4i+5i-18i-10=0

We add all the numbers together, and all the variables

-26i^2-9i-10=0

a = -26; b = -9; c = -10;
Δ = b2-4ac
Δ = -92-4·(-26)·(-10)
Δ = -959
Delta is less than zero, so there is no solution for the equation

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