(5-2i)(4-i)=

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Solution for (5-2i)(4-i)= equation:


Simplifying
(5 + -2i)(4 + -1i) = 0

Multiply (5 + -2i) * (4 + -1i)
(5(4 + -1i) + -2i * (4 + -1i)) = 0
((4 * 5 + -1i * 5) + -2i * (4 + -1i)) = 0
((20 + -5i) + -2i * (4 + -1i)) = 0
(20 + -5i + (4 * -2i + -1i * -2i)) = 0
(20 + -5i + (-8i + 2i2)) = 0

Combine like terms: -5i + -8i = -13i
(20 + -13i + 2i2) = 0

Solving
20 + -13i + 2i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(5 + -2i)(4 + -1i) = 0

Subproblem 1

Set the factor '(5 + -2i)' equal to zero and attempt to solve: Simplifying 5 + -2i = 0 Solving 5 + -2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2i = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2i = 0 + -5 -2i = 0 + -5 Combine like terms: 0 + -5 = -5 -2i = -5 Divide each side by '-2'. i = 2.5 Simplifying i = 2.5

Subproblem 2

Set the factor '(4 + -1i)' equal to zero and attempt to solve: Simplifying 4 + -1i = 0 Solving 4 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1i = 0 + -4 -1i = 0 + -4 Combine like terms: 0 + -4 = -4 -1i = -4 Divide each side by '-1'. i = 4 Simplifying i = 4

Solution

i = {2.5, 4}

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