(5-2i)(5-2i)=0

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Solution for (5-2i)(5-2i)=0 equation: 



(5-2i)(5-2i)=0

We add all the numbers together, and all the variables

(-2i+5)(-2i+5)=0

We multiply parentheses ..

(+4i^2-10i-10i+25)=0

We get rid of parentheses

4i^2-10i-10i+25=0

We add all the numbers together, and all the variables

4i^2-20i+25=0

a = 4; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{20}{8}=2+1/2$

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