(5-2i)=(-1+3i)

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Solution for (5-2i)=(-1+3i) equation: 



(5-2i)=(-1+3i)

We move all terms to the left:

(5-2i)-((-1+3i))=0

We add all the numbers together, and all the variables

(-2i+5)-((3i-1))=0

We get rid of parentheses

-2i-((3i-1))+5=0



We calculate terms in parentheses: -((3i-1)), so:

(3i-1)

We get rid of parentheses

3i-1

Back to the equation:

-(3i-1)



We get rid of parentheses

-2i-3i+1+5=0

We add all the numbers together, and all the variables

-5i+6=0

We move all terms containing i to the left, all other terms to the right

-5i=-6

i=-6/-5

i=1+1/5

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