(5-2v)=-4(3v+1)

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Solution for (5-2v)=-4(3v+1) equation: 



(5-2v)=-4(3v+1)

We move all terms to the left:

(5-2v)-(-4(3v+1))=0

We add all the numbers together, and all the variables

(-2v+5)-(-4(3v+1))=0

We get rid of parentheses

-2v-(-4(3v+1))+5=0



We calculate terms in parentheses: -(-4(3v+1)), so:

-4(3v+1)

We multiply parentheses

-12v-4

Back to the equation:

-(-12v-4)



We get rid of parentheses

-2v+12v+4+5=0

We add all the numbers together, and all the variables

10v+9=0

We move all terms containing v to the left, all other terms to the right

10v=-9

v=-9/10

v=-9/10

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