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(5-2v)=4-8(v-2)
We move all terms to the left:
(5-2v)-(4-8(v-2))=0
We add all the numbers together, and all the variables
(-2v+5)-(4-8(v-2))=0
We get rid of parentheses
-2v-(4-8(v-2))+5=0
We calculate terms in parentheses: -(4-8(v-2)), so:We get rid of parentheses
4-8(v-2)
determiningTheFunctionDomain -8(v-2)+4
We multiply parentheses
-8v+16+4
We add all the numbers together, and all the variables
-8v+20
Back to the equation:
-(-8v+20)
-2v+8v-20+5=0
We add all the numbers together, and all the variables
6v-15=0
We move all terms containing v to the left, all other terms to the right
6v=15
v=15/6
v=2+1/2
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