(5-2x)(2x-5)=0

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Solution for (5-2x)(2x-5)=0 equation: 



(5-2x)(2x-5)=0

We add all the numbers together, and all the variables

(-2x+5)(2x-5)=0

We multiply parentheses ..

(-4x^2+10x+10x-25)=0

We get rid of parentheses

-4x^2+10x+10x-25=0

We add all the numbers together, and all the variables

-4x^2+20x-25=0

a = -4; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·(-4)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-8}=2+1/2$

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