(5-2x)=4(3-x)-19

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Solution for (5-2x)=4(3-x)-19 equation: 



(5-2x)=4(3-x)-19

We move all terms to the left:

(5-2x)-(4(3-x)-19)=0

We add all the numbers together, and all the variables

(-2x+5)-(4(-1x+3)-19)=0

We get rid of parentheses

-2x-(4(-1x+3)-19)+5=0



We calculate terms in parentheses: -(4(-1x+3)-19), so:

4(-1x+3)-19

We multiply parentheses

-4x+12-19

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We get rid of parentheses

-2x+4x+7+5=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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