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(5-2x)=7-2(x+3)
We move all terms to the left:
(5-2x)-(7-2(x+3))=0
We add all the numbers together, and all the variables
(-2x+5)-(7-2(x+3))=0
We get rid of parentheses
-2x-(7-2(x+3))+5=0
We calculate terms in parentheses: -(7-2(x+3)), so:We get rid of parentheses
7-2(x+3)
determiningTheFunctionDomain -2(x+3)+7
We multiply parentheses
-2x-6+7
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
-2x+2x-1+5=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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