(5-3i)3=a+ib

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Solution for (5-3i)3=a+ib equation:


Simplifying
(5 + -3i) * 3 = a + ib

Reorder the terms for easier multiplication:
3(5 + -3i) = a + ib
(5 * 3 + -3i * 3) = a + ib
(15 + -9i) = a + ib

Solving
15 + -9i = a + bi

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1bi' to each side of the equation.
15 + -1bi + -9i = a + bi + -1bi

Combine like terms: bi + -1bi = 0
15 + -1bi + -9i = a + 0
15 + -1bi + -9i = a

Add '-15' to each side of the equation.
15 + -1bi + -15 + -9i = -15 + a

Reorder the terms:
15 + -15 + -1bi + -9i = -15 + a

Combine like terms: 15 + -15 = 0
0 + -1bi + -9i = -15 + a
-1bi + -9i = -15 + a

Reorder the terms:
15 + -1a + -1bi + -9i = -15 + a + 15 + -1a

Reorder the terms:
15 + -1a + -1bi + -9i = -15 + 15 + a + -1a

Combine like terms: -15 + 15 = 0
15 + -1a + -1bi + -9i = 0 + a + -1a
15 + -1a + -1bi + -9i = a + -1a

Combine like terms: a + -1a = 0
15 + -1a + -1bi + -9i = 0

The solution to this equation could not be determined.

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