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(5-3i)=(6i)
We move all terms to the left:
(5-3i)-((6i))=0
determiningTheFunctionDomain (5-3i)-6i=0
We add all the numbers together, and all the variables
(-3i+5)-6i=0
We add all the numbers together, and all the variables
-6i+(-3i+5)=0
We get rid of parentheses
-6i-3i+5=0
We add all the numbers together, and all the variables
-9i+5=0
We move all terms containing i to the left, all other terms to the right
-9i=-5
i=-5/-9
i=5/9
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