(5-3m)(2-5m)=0

Solution for (5-3m)(2-5m)=0 equation:

(5-3m)(2-5m)=0

We add all the numbers together, and all the variables

(-3m+5)(-5m+2)=0

We multiply parentheses ..

(+15m^2-6m-25m+10)=0

We get rid of parentheses

15m^2-6m-25m+10=0

We add all the numbers together, and all the variables

15m^2-31m+10=0

a = 15; b = -31; c = +10;
Δ = b2-4ac
Δ = -312-4·15·10
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-19}{2*15}=\frac{12}{30}
=2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+19}{2*15}=\frac{50}{30}
=1+2/3
$