(5-9a)=(4a2+6a-3)

Solution for (5-9a)=(4a2+6a-3) equation:

(5-9a)=(4a^2+6a-3)

We move all terms to the left:

(5-9a)-((4a^2+6a-3))=0

We add all the numbers together, and all the variables

(-9a+5)-((4a^2+6a-3))=0

We get rid of parentheses

-9a-((4a^2+6a-3))+5=0


We calculate terms in parentheses: -((4a^2+6a-3)), so:

(4a^2+6a-3)

We get rid of parentheses

4a^2+6a-3

Back to the equation:

-(4a^2+6a-3)


We get rid of parentheses

-4a^2-9a-6a+3+5=0

We add all the numbers together, and all the variables

-4a^2-15a+8=0

a = -4; b = -15; c = +8;
Δ = b2-4ac
Δ = -152-4·(-4)·8
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{353}}{2*-4}=\frac{15-\sqrt{353}}{-8}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{353}}{2*-4}=\frac{15+\sqrt{353}}{-8}
$