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(5-a)(-2-a)-18=0
We add all the numbers together, and all the variables
(-1a+5)(-1a-2)-18=0
We multiply parentheses ..
(+a^2+2a-5a-10)-18=0
We get rid of parentheses
a^2+2a-5a-10-18=0
We add all the numbers together, and all the variables
a^2-3a-28=0
a = 1; b = -3; c = -28;
Δ = b2-4ac
Δ = -32-4·1·(-28)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-11}{2*1}=\frac{-8}{2} =-4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+11}{2*1}=\frac{14}{2} =7 $
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