(5-c)(c+2)(c-8)=0

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Solution for (5-c)(c+2)(c-8)=0 equation:


Simplifying
(5 + -1c)(c + 2)(c + -8) = 0

Reorder the terms:
(5 + -1c)(2 + c)(c + -8) = 0

Reorder the terms:
(5 + -1c)(2 + c)(-8 + c) = 0

Multiply (5 + -1c) * (2 + c)
(5(2 + c) + -1c * (2 + c))(-8 + c) = 0
((2 * 5 + c * 5) + -1c * (2 + c))(-8 + c) = 0
((10 + 5c) + -1c * (2 + c))(-8 + c) = 0
(10 + 5c + (2 * -1c + c * -1c))(-8 + c) = 0
(10 + 5c + (-2c + -1c2))(-8 + c) = 0

Combine like terms: 5c + -2c = 3c
(10 + 3c + -1c2)(-8 + c) = 0

Multiply (10 + 3c + -1c2) * (-8 + c)
(10(-8 + c) + 3c * (-8 + c) + -1c2 * (-8 + c)) = 0
((-8 * 10 + c * 10) + 3c * (-8 + c) + -1c2 * (-8 + c)) = 0
((-80 + 10c) + 3c * (-8 + c) + -1c2 * (-8 + c)) = 0
(-80 + 10c + (-8 * 3c + c * 3c) + -1c2 * (-8 + c)) = 0
(-80 + 10c + (-24c + 3c2) + -1c2 * (-8 + c)) = 0
(-80 + 10c + -24c + 3c2 + (-8 * -1c2 + c * -1c2)) = 0
(-80 + 10c + -24c + 3c2 + (8c2 + -1c3)) = 0

Combine like terms: 10c + -24c = -14c
(-80 + -14c + 3c2 + 8c2 + -1c3) = 0

Combine like terms: 3c2 + 8c2 = 11c2
(-80 + -14c + 11c2 + -1c3) = 0

Solving
-80 + -14c + 11c2 + -1c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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