(5-u)(5u-2)=0

Solution for (5-u)(5u-2)=0 equation:

(5-u)(5u-2)=0

We add all the numbers together, and all the variables

(-1u+5)(5u-2)=0

We multiply parentheses ..

(-5u^2+2u+25u-10)=0

We get rid of parentheses

-5u^2+2u+25u-10=0

We add all the numbers together, and all the variables

-5u^2+27u-10=0

a = -5; b = 27; c = -10;
Δ = b2-4ac
Δ = 272-4·(-5)·(-10)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-23}{2*-5}=\frac{-50}{-10}
=+5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+23}{2*-5}=\frac{-4}{-10}
=2/5
$