(5-v)(5v-3)=0

Solution for (5-v)(5v-3)=0 equation:

(5-v)(5v-3)=0

We add all the numbers together, and all the variables

(-1v+5)(5v-3)=0

We multiply parentheses ..

(-5v^2+3v+25v-15)=0

We get rid of parentheses

-5v^2+3v+25v-15=0

We add all the numbers together, and all the variables

-5v^2+28v-15=0

a = -5; b = 28; c = -15;
Δ = b2-4ac
Δ = 282-4·(-5)·(-15)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-22}{2*-5}=\frac{-50}{-10}
=+5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+22}{2*-5}=\frac{-6}{-10}
=3/5
$