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(5-x)(2x+9)=0
We add all the numbers together, and all the variables
(-1x+5)(2x+9)=0
We multiply parentheses ..
(-2x^2-9x+10x+45)=0
We get rid of parentheses
-2x^2-9x+10x+45=0
We add all the numbers together, and all the variables
-2x^2+x+45=0
a = -2; b = 1; c = +45;
Δ = b2-4ac
Δ = 12-4·(-2)·45
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*-2}=\frac{18}{-4} =-4+1/2 $
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