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(5-x)(2x-3)=4x+7
We move all terms to the left:
(5-x)(2x-3)-(4x+7)=0
We add all the numbers together, and all the variables
(-1x+5)(2x-3)-(4x+7)=0
We get rid of parentheses
(-1x+5)(2x-3)-4x-7=0
We multiply parentheses ..
(-2x^2+3x+10x-15)-4x-7=0
We get rid of parentheses
-2x^2+3x+10x-4x-15-7=0
We add all the numbers together, and all the variables
-2x^2+9x-22=0
a = -2; b = 9; c = -22;
Δ = b2-4ac
Δ = 92-4·(-2)·(-22)
Δ = -95
Delta is less than zero, so there is no solution for the equation
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