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(5-x)(5-x)+16=0
We add all the numbers together, and all the variables
(-1x+5)(-1x+5)+16=0
We multiply parentheses ..
(+x^2-5x-5x+25)+16=0
We get rid of parentheses
x^2-5x-5x+25+16=0
We add all the numbers together, and all the variables
x^2-10x+41=0
a = 1; b = -10; c = +41;
Δ = b2-4ac
Δ = -102-4·1·41
Δ = -64
Delta is less than zero, so there is no solution for the equation
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