(5-x)(5x-1)=0

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Solution for (5-x)(5x-1)=0 equation:



(5-x)(5x-1)=0
We add all the numbers together, and all the variables
(-1x+5)(5x-1)=0
We multiply parentheses ..
(-5x^2+x+25x-5)=0
We get rid of parentheses
-5x^2+x+25x-5=0
We add all the numbers together, and all the variables
-5x^2+26x-5=0
a = -5; b = 26; c = -5;
Δ = b2-4ac
Δ = 262-4·(-5)·(-5)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-24}{2*-5}=\frac{-50}{-10} =+5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+24}{2*-5}=\frac{-2}{-10} =1/5 $

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