(5-x)(x-3)=0

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Solution for (5-x)(x-3)=0 equation:



(5-x)(x-3)=0
We add all the numbers together, and all the variables
(-1x+5)(x-3)=0
We multiply parentheses ..
(-1x^2+3x+5x-15)=0
We get rid of parentheses
-1x^2+3x+5x-15=0
We add all the numbers together, and all the variables
-1x^2+8x-15=0
a = -1; b = 8; c = -15;
Δ = b2-4ac
Δ = 82-4·(-1)·(-15)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*-1}=\frac{-10}{-2} =+5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*-1}=\frac{-6}{-2} =+3 $

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