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(5-x)(x-4)=20-3x
We move all terms to the left:
(5-x)(x-4)-(20-3x)=0
We add all the numbers together, and all the variables
(-1x+5)(x-4)-(-3x+20)=0
We get rid of parentheses
(-1x+5)(x-4)+3x-20=0
We multiply parentheses ..
(-1x^2+4x+5x-20)+3x-20=0
We get rid of parentheses
-1x^2+4x+5x+3x-20-20=0
We add all the numbers together, and all the variables
-1x^2+12x-40=0
a = -1; b = 12; c = -40;
Δ = b2-4ac
Δ = 122-4·(-1)·(-40)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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