(5-x)/3=(x+4)/2

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Solution for (5-x)/3=(x+4)/2 equation: 



(5-x)/3=(x+4)/2

We move all terms to the left:

(5-x)/3-((x+4)/2)=0

We add all the numbers together, and all the variables

(-1x+5)/3-((x+4)/2)=0

We calculate fractions


(-x)/()+(-((x+4)*3)/()=0



We calculate terms in parentheses: +(-((x+4)*3)/(), so:

-((x+4)*3)/(

We multiply all the terms by the denominator


-((x+4)*3)



We calculate terms in parentheses: -((x+4)*3), so:

(x+4)*3

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-3x-12

Back to the equation:

+(-3x-12)



We add all the numbers together, and all the variables

(-1x)/()+(-3x-12)=0

We get rid of parentheses

(-1x)/()-3x-12=0

We multiply all the terms by the denominator


(-1x)-3x*()-12*()=0

We add all the numbers together, and all the variables

(-1x)-3x*()=0

We get rid of parentheses

-1x-3x*()=0

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