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(5-x)4-2(x-3)=x-4-3(x+2
We move all terms to the left:
(5-x)4-2(x-3)-(x-4-3(x+2)=0
We add all the numbers together, and all the variables
(-1x+5)4-2(x-3)-(x-4-3(x+2)=0
We multiply parentheses
-4x-2x-(x-4-3(x+2)+20+6=0
We add all the numbers together, and all the variables
-6x-(x-4-3(x+2)+20+6=0
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