(5-x/5+x)=(5-x)(5+x)

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Solution for (5-x/5+x)=(5-x)(5+x) equation:



(5-x/5+x)=(5-x)(5+x)
We move all terms to the left:
(5-x/5+x)-((5-x)(5+x))=0
Domain of the equation: 5+x)!=0
We move all terms containing x to the left, all other terms to the right
x)!=-5
x!=-5/1
x!=-5
x∈R
We add all the numbers together, and all the variables
(x-x/5+5)-((-1x+5)(x+5))=0
We get rid of parentheses
x-x/5-((-1x+5)(x+5))+5=0
We multiply parentheses ..
-((-1x^2-5x+5x+25))+x-x/5+5=0
We multiply all the terms by the denominator
-(((-1x^2-5x+5x+25)))*5+x*5-x+5*5=0
We add all the numbers together, and all the variables
-(((-1x^2-5x+5x+25)))*5-1x+x*5+25=0
Wy multiply elements
-(((-1x^2-5x+5x+25)))*5-1x+5x+25=0
We add all the numbers together, and all the variables
-(((-1x^2-5x+5x+25)))*5+4x+25=0
We move all terms containing x to the left, all other terms to the right
-(((-1x^2-5x+5x+25)))*5+4x=-25

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