(5-y)(2y+1)=0

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Solution for (5-y)(2y+1)=0 equation:


Simplifying
(5 + -1y)(2y + 1) = 0

Reorder the terms:
(5 + -1y)(1 + 2y) = 0

Multiply (5 + -1y) * (1 + 2y)
(5(1 + 2y) + -1y * (1 + 2y)) = 0
((1 * 5 + 2y * 5) + -1y * (1 + 2y)) = 0
((5 + 10y) + -1y * (1 + 2y)) = 0
(5 + 10y + (1 * -1y + 2y * -1y)) = 0
(5 + 10y + (-1y + -2y2)) = 0

Combine like terms: 10y + -1y = 9y
(5 + 9y + -2y2) = 0

Solving
5 + 9y + -2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(5 + -1y)(1 + 2y) = 0

Subproblem 1

Set the factor '(5 + -1y)' equal to zero and attempt to solve: Simplifying 5 + -1y = 0 Solving 5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1y = 0 + -5 -1y = 0 + -5 Combine like terms: 0 + -5 = -5 -1y = -5 Divide each side by '-1'. y = 5 Simplifying y = 5

Subproblem 2

Set the factor '(1 + 2y)' equal to zero and attempt to solve: Simplifying 1 + 2y = 0 Solving 1 + 2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2y = 0 + -1 2y = 0 + -1 Combine like terms: 0 + -1 = -1 2y = -1 Divide each side by '2'. y = -0.5 Simplifying y = -0.5

Solution

y = {5, -0.5}

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