(5.2-2x)(5.2-2x)=0

Solution for (5.2-2x)(5.2-2x)=0 equation:

(5.2-2x)(5.2-2x)=0

We add all the numbers together, and all the variables

(-2x+5.2)(-2x+5.2)=0

We multiply parentheses ..

(+4x^2-10.4x-10.4x+27.04)=0

We get rid of parentheses

4x^2-10.4x-10.4x+27.04=0

We add all the numbers together, and all the variables

4x^2-20.8x+27.04=0

a = 4; b = -20.8; c = +27.04;
Δ = b2-4ac
Δ = -20.82-4·4·27.04
Δ = 5.6843418860808E-14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20.8)-\sqrt{5.6843418860808E-14}}{2*4}=\frac{20.8-\sqrt{5.6843418860808E-14}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20.8)+\sqrt{5.6843418860808E-14}}{2*4}=\frac{20.8+\sqrt{5.6843418860808E-14}}{8}
$