(5/(2y+4))+2=-(6/(y+2))

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Solution for (5/(2y+4))+2=-(6/(y+2)) equation: 


D( y )

y+2 = 0

2*y+4 = 0

y+2 = 0

y+2 = 0

y+2 = 0 // - 2

y = -2

2*y+4 = 0

2*y+4 = 0

2*y+4 = 0 // - 4

2*y = -4 // : 2

y = -4/2

y = -2

y in (-oo:-2) U (-2:+oo)

5/(2*y+4)+2 = -(6/(y+2)) // + 6/(y+2)

5/(2*y+4)+6/(y+2)+2 = 0

(5*(y+2))/((2*y+4)*(y+2))+(6*(2*y+4))/((2*y+4)*(y+2))+(2*(2*y+4)*(y+2))/((2*y+4)*(y+2)) = 0

5*(y+2)+6*(2*y+4)+2*(2*y+4)*(y+2) = 0

4*y^2+17*y+16*y+16+34 = 0

4*y^2+33*y+50 = 0

4*y^2+33*y+50 = 0

4*y^2+33*y+50 = 0

DELTA = 33^2-(4*4*50)

DELTA = 289

DELTA > 0

y = (289^(1/2)-33)/(2*4) or y = (-289^(1/2)-33)/(2*4)

y = -2 or y = -25/4

(y+25/4)*(y+2) = 0

((y+25/4)*(y+2))/((2*y+4)*(y+2)) = 0

((y+25/4)*(y+2))/((2*y+4)*(y+2)) = 0 // * (2*y+4)*(y+2)

(y+25/4)*(y+2) = 0

( y+2 )

y+2 = 0 // - 2

y = -2

( y+25/4 )

y+25/4 = 0 // - 25/4

y = -25/4

y in { -2} 

y = -25/4

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