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(5/(3x-9))-(2/(3x))=0
Domain of the equation: (3x-9))!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(5/(3x-9))-(+2/3x)=0
We get rid of parentheses
(5/(3x-9))-2/3x=0
We calculate fractions
((5*3x)/(-18x^2)+(-6x)/(-18x^2)=0
We calculate terms in parentheses: +((5*3x)/(-18x^2)+(-6x)/(-18x^2), so:
(5*3x)/(-18x^2)+(-6x)/(-18x^2
We add all the numbers together, and all the variables
(+5*3x)/(-18x^2)+(-6x)/(-18x^2
We calculate fractions
((+5*3x)*(-18x^2)/((-18x^2)*(-18x^2)+((-6x)*(-18x^2))/((-18x^2)*(-18x^2)
We calculate terms in parentheses: +((+5*3x)*(-18x^2)/((-18x^2)*(-18x^2)+((-6x)*(-18x^2))/((-18x^2)*(-18x^2), so:
(+5*3x)*(-18x^2)/((-18x^2)*(-18x^2)+((-6x)*(-18x^2))/((-18x^2)*(-18x^2
We can not solve this equation
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