(5/(x+3))+(4/(x+2))=2

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Solution for (5/(x+3))+(4/(x+2))=2 equation:



(5/(x+3))+(4/(x+2))=2
We move all terms to the left:
(5/(x+3))+(4/(x+2))-(2)=0
Domain of the equation: (x+3))!=0
x∈R
Domain of the equation: (x+2))!=0
x∈R
We calculate fractions
(5x+10)/((x+3))*x+(4x+12)/((x+3))*x-2=0
We multiply all the terms by the denominator
(5x+10)+(4x+12)-2*((x+3))*x=0
We get rid of parentheses
5x+4x-2*((x+3))*x+10+12=0
We add all the numbers together, and all the variables
9x-2*((x+3))*x+22=0
We move all terms containing x to the left, all other terms to the right
9x-2*((x+3))*x=-22

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