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D( x )
x-5 = 0
5*x-25 = 0
30/(5*x-25) = 0
x-5 = 0
x-5 = 0
x-5 = 0 // + 5
x = 5
5*x-25 = 0
5*x-25 = 0
5*x-25 = 0 // + 25
5*x = 25 // : 5
x = 25/5
x = 5
30/(5*x-25) = 0
30/(5*x-25) = 0
x in (-oo:5) U (5:+oo)
(5/(x-5))/(30/(5*x-25)) = 0
(5*(5*x-25))/(30*(x-5)) = 0
5*x-25 = 0 // + 25
5*x = 25 // : 5
x = 25/5
x = 5
x in { 5}
x belongs to the empty set
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