(5/(y+3))+(3/(y-2))=(8/(y+6))

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Solution for (5/(y+3))+(3/(y-2))=(8/(y+6)) equation:


D( y )

y+3 = 0

y+6 = 0

y-2 = 0

y+3 = 0

y+3 = 0

y+3 = 0 // - 3

y = -3

y+6 = 0

y+6 = 0

y+6 = 0 // - 6

y = -6

y-2 = 0

y-2 = 0

y-2 = 0 // + 2

y = 2

y in (-oo:-6) U (-6:-3) U (-3:2) U (2:+oo)

5/(y+3)+3/(y-2) = 8/(y+6) // - 8/(y+6)

5/(y+3)+3/(y-2)-(8/(y+6)) = 0

5/(y+3)+3/(y-2)-8*(y+6)^-1 = 0

5/(y+3)+3/(y-2)-8/(y+6) = 0

(5*(y-2)*(y+6))/((y+3)*(y-2)*(y+6))+(3*(y+3)*(y+6))/((y+3)*(y-2)*(y+6))+(-8*(y+3)*(y-2))/((y+3)*(y-2)*(y+6)) = 0

5*(y-2)*(y+6)+3*(y+3)*(y+6)-8*(y+3)*(y-2) = 0

8*y^2-8*y^2+47*y-8*y-6+48 = 0

39*y+42 = 0

(39*y+42)/((y+3)*(y-2)*(y+6)) = 0

(39*y+42)/((y+3)*(y-2)*(y+6)) = 0 // * (y+3)*(y-2)*(y+6)

39*y+42 = 0

39*y+42 = 0 // - 42

39*y = -42 // : 39

y = -42/39

y = -14/13

y = -14/13

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