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(5/11)x+2=1
We move all terms to the left:
(5/11)x+2-(1)=0
Domain of the equation: 11)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/11)x+2-1=0
We add all the numbers together, and all the variables
(+5/11)x+1=0
We multiply parentheses
5x^2+1=0
a = 5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·5·1
Δ = -20
Delta is less than zero, so there is no solution for the equation
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