(5/12d)+(1/6d)+(1/3d)+(1/12d)=6

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Solution for (5/12d)+(1/6d)+(1/3d)+(1/12d)=6 equation: 



(5/12d)+(1/6d)+(1/3d)+(1/12d)=6

We move all terms to the left:

(5/12d)+(1/6d)+(1/3d)+(1/12d)-(6)=0



Domain of the equation: 12d)!=0

d!=0/1

d!=0

d∈R





Domain of the equation: 6d)!=0

d!=0/1

d!=0

d∈R





Domain of the equation: 3d)!=0

d!=0/1

d!=0

d∈R



We add all the numbers together, and all the variables

(+5/12d)+(+1/6d)+(+1/3d)+(+1/12d)-6=0

We get rid of parentheses

5/12d+1/6d+1/3d+1/12d-6=0

We calculate fractions

We do not support edpression: d^3

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