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(5/2)*z-7=23
We move all terms to the left:
(5/2)*z-7-(23)=0
Domain of the equation: 2)*z!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
(+5/2)*z-7-23=0
We add all the numbers together, and all the variables
(+5/2)*z-30=0
We multiply parentheses
5z^2-30=0
a = 5; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·5·(-30)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*5}=\frac{0-10\sqrt{6}}{10} =-\frac{10\sqrt{6}}{10} =-\sqrt{6} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*5}=\frac{0+10\sqrt{6}}{10} =\frac{10\sqrt{6}}{10} =\sqrt{6} $
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