(5/2)+(3/2)y=2y-3

Solution for (5/2)+(3/2)y=2y-3 equation:

(5/2)+(3/2)y=2y-3

We move all terms to the left:

(5/2)+(3/2)y-(2y-3)=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+3/2)y-(2y-3)+(+5/2)=0

We multiply parentheses

3y^2-(2y-3)+(+5/2)=0

We get rid of parentheses

3y^2-2y+3+5/2=0

We multiply all the terms by the denominator


3y^2*2-2y*2+5+3*2=0

We add all the numbers together, and all the variables

3y^2*2-2y*2+11=0

Wy multiply elements

6y^2-4y+11=0

a = 6; b = -4; c = +11;
Δ = b2-4ac
Δ = -42-4·6·11
Δ = -248
Delta is less than zero, so there is no solution for the equation