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(5/2)+(5/2)x=2x-3
We move all terms to the left:
(5/2)+(5/2)x-(2x-3)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/2)x-(2x-3)+(+5/2)=0
We multiply parentheses
5x^2-(2x-3)+(+5/2)=0
We get rid of parentheses
5x^2-2x+3+5/2=0
We multiply all the terms by the denominator
5x^2*2-2x*2+5+3*2=0
We add all the numbers together, and all the variables
5x^2*2-2x*2+11=0
Wy multiply elements
10x^2-4x+11=0
a = 10; b = -4; c = +11;
Δ = b2-4ac
Δ = -42-4·10·11
Δ = -424
Delta is less than zero, so there is no solution for the equation
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