(5/2)-(7/2x)=(4/x)

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Solution for (5/2)-(7/2x)=(4/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/2-((7/2)*x) = 4/x // - 4/x

5/2-((7/2)*x)-(4/x) = 0

(-7/2)*x-4*x^-1+5/2 = 0

5/2*x^0-7/2*x^1-4*x^-1 = 0

(5/2*x^1-7/2*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^1-7/2*x^2-4*x^0) = 0

x^1

(-7/2)*x^2+(5/2)*x-4 = 0

(-7/2)*x^2+(5/2)*x-4 = 0

DELTA = (5/2)^2-(-4*4*(-7/2))

DELTA = -199/4

DELTA < 0

x in { } 

x belongs to the empty set

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