(5/2)k=5

Solution for (5/2)k=5 equation:

(5/2)k=5

We move all terms to the left:

(5/2)k-(5)=0


Domain of the equation: 2)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(+5/2)k-5=0

We multiply parentheses

5k^2-5=0

a = 5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·5·(-5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*5}=\frac{-10}{10}
=-1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*5}=\frac{10}{10}
=1
$