(5/2)k=5

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Solution for (5/2)k=5 equation:



(5/2)k=5
We move all terms to the left:
(5/2)k-(5)=0
Domain of the equation: 2)k!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
(+5/2)k-5=0
We multiply parentheses
5k^2-5=0
a = 5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·5·(-5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*5}=\frac{-10}{10} =-1 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*5}=\frac{10}{10} =1 $

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