(5/2)x+(1/2)x=7+(7/2)x

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Solution for (5/2)x+(1/2)x=7+(7/2)x equation: 



(5/2)x+(1/2)x=7+(7/2)x

We move all terms to the left:

(5/2)x+(1/2)x-(7+(7/2)x)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/2)x+(+1/2)x-(7+(+7/2)x)=0

We multiply parentheses

5x^2+x^2-(7+(+7/2)x)=0

We multiply all the terms by the denominator


5x^2*2)x)+x^2*2)x)-(7+(+7=0

Wy multiply elements

20x^4=0

We do not support expression: x^4

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