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(5/2)y=-9y
We move all terms to the left:
(5/2)y-(-9y)=0
Domain of the equation: 2)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/2)y-(-9y)=0
We multiply parentheses
5y^2-(-9y)=0
We get rid of parentheses
5y^2+9y=0
a = 5; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·5·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:y_{1}=\frac{-b-\sqrt{\Delta}}{2a}y_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{81}=9y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*5}=\frac{-18}{10} =-1+4/5y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*5}=\frac{0}{10} =0
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