(5/2b)-5=(1/2b)+1

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Solution for (5/2b)-5=(1/2b)+1 equation: 



(5/2b)-5=(1/2b)+1

We move all terms to the left:

(5/2b)-5-((1/2b)+1)=0



Domain of the equation: 2b)!=0

b!=0/1

b!=0

b∈R





Domain of the equation: 2b)+1)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+5/2b)-((+1/2b)+1)-5=0

We get rid of parentheses

5/2b-((+1/2b)+1)-5=0

We calculate fractions


10b/4b^2+(-((+1*2b)/4b^2-5=0

We calculate fractions

We do not support ebpression: b^4

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