(5/2y)-(4/y)=(1/2)

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Solution for (5/2y)-(4/y)=(1/2) equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(5/2)*y-(4/y) = 1/2 // - 1/2

(5/2)*y-(4/y)-(1/2) = 0

(5/2)*y-4*y^-1-1/2 = 0

5/2*y^1-4*y^-1-1/2*y^0 = 0

(5/2*y^2-1/2*y^1-4*y^0)/(y^1) = 0 // * y^2

y^1*(5/2*y^2-1/2*y^1-4*y^0) = 0

y^1

(5/2)*y^2+(-1/2)*y-4 = 0

(5/2)*y^2+(-1/2)*y-4 = 0

DELTA = (-1/2)^2-(-4*4*(5/2))

DELTA = 161/4

DELTA > 0

y = ((161/4)^(1/2)-(-1/2))/(2*(5/2)) or y = (-(-1/2)-(161/4)^(1/2))/(2*(5/2))

y = ((161/4)^(1/2)+1/2)/5 or y = (1/2-(161/4)^(1/2))/5

y in { (1/2-(161/4)^(1/2))/5, ((161/4)^(1/2)+1/2)/5}

y in { (1/2-(161/4)^(1/2))/5, ((161/4)^(1/2)+1/2)/5 }

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