(5/2y)-(5/y)=(5/2)

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Solution for (5/2y)-(5/y)=(5/2) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(5/2)*y-(5/y) = 5/2 // - 5/2

(5/2)*y-(5/y)-(5/2) = 0

(5/2)*y-5*y^-1-5/2 = 0

5/2*y^1-5*y^-1-5/2*y^0 = 0

(5/2*y^2-5/2*y^1-5*y^0)/(y^1) = 0 // * y^2

y^1*(5/2*y^2-5/2*y^1-5*y^0) = 0

y^1

(5/2)*y^2+(-5/2)*y-5 = 0

(5/2)*y^2+(-5/2)*y-5 = 0

DELTA = (-5/2)^2-(-5*4*(5/2))

DELTA = 225/4

DELTA > 0

y = ((225/4)^(1/2)-(-5/2))/(2*(5/2)) or y = (-(-5/2)-(225/4)^(1/2))/(2*(5/2))

y = 2 or y = -1

y in { -1, 2} 

y in { -1, 2 }

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