(5/3)=(v-5)/2

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Solution for (5/3)=(v-5)/2 equation: 



(5/3)=(v-5)/2

We move all terms to the left:

(5/3)-((v-5)/2)=0

We add all the numbers together, and all the variables

-((v-5)/2)+(+5/3)=0

We get rid of parentheses

-((v-5)/2)+5/3=0

We calculate fractions


(-((v-5)*3)/()+()/()=0



We calculate terms in parentheses: +(-((v-5)*3)/()+()/(), so:

-((v-5)*3)/()+()/(

We add all the numbers together, and all the variables

-((v-5)*3)/()+1

We multiply all the terms by the denominator


-((v-5)*3)+1*()



We calculate terms in parentheses: -((v-5)*3), so:

(v-5)*3

We multiply parentheses

3v-15

Back to the equation:

-(3v-15)



We add all the numbers together, and all the variables

-(3v-15)

We get rid of parentheses

-3v+15

Back to the equation:

+(-3v+15)



We get rid of parentheses

-3v+15=0

We move all terms containing v to the left, all other terms to the right

-3v=-15

v=-15/-3

v=+5

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