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(5/3)j-6=94
We move all terms to the left:
(5/3)j-6-(94)=0
Domain of the equation: 3)j!=0We add all the numbers together, and all the variables
j!=0/1
j!=0
j∈R
(+5/3)j-6-94=0
We add all the numbers together, and all the variables
(+5/3)j-100=0
We multiply parentheses
5j^2-100=0
a = 5; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·5·(-100)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{5}}{2*5}=\frac{0-20\sqrt{5}}{10} =-\frac{20\sqrt{5}}{10} =-2\sqrt{5} $$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{5}}{2*5}=\frac{0+20\sqrt{5}}{10} =\frac{20\sqrt{5}}{10} =2\sqrt{5} $
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